(x+1)(x-1)-x^2+2x=3

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Solution for (x+1)(x-1)-x^2+2x=3 equation:


Simplifying
(x + 1)(x + -1) + -1x2 + 2x = 3

Reorder the terms:
(1 + x)(x + -1) + -1x2 + 2x = 3

Reorder the terms:
(1 + x)(-1 + x) + -1x2 + 2x = 3

Multiply (1 + x) * (-1 + x)
(1(-1 + x) + x(-1 + x)) + -1x2 + 2x = 3
((-1 * 1 + x * 1) + x(-1 + x)) + -1x2 + 2x = 3
((-1 + 1x) + x(-1 + x)) + -1x2 + 2x = 3
(-1 + 1x + (-1 * x + x * x)) + -1x2 + 2x = 3
(-1 + 1x + (-1x + x2)) + -1x2 + 2x = 3

Combine like terms: 1x + -1x = 0
(-1 + 0 + x2) + -1x2 + 2x = 3
(-1 + x2) + -1x2 + 2x = 3

Reorder the terms:
-1 + 2x + x2 + -1x2 = 3

Combine like terms: x2 + -1x2 = 0
-1 + 2x + 0 = 3
-1 + 2x = 3

Solving
-1 + 2x = 3

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 2x = 3 + 1

Combine like terms: -1 + 1 = 0
0 + 2x = 3 + 1
2x = 3 + 1

Combine like terms: 3 + 1 = 4
2x = 4

Divide each side by '2'.
x = 2

Simplifying
x = 2

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